Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls in rotation per second (rps) D = diameter of rolls, m) ?
Correct answer: A. 3.6 V.W.Dr.ρ
- A. 3.6 V.W.Dr.ρ
- B. 3.6 V.W. ρ
- C. 3.6 W.Dr.ρ
- D. 3.6 V.W.Dr/ρ
Explanation
The roll gap gives the approximate bed thickness, so the volumetric throughput is V × W × Dr; multiplying by density gives mass flow. Converting kg/s to tons/hour introduces the factor 3.6, giving 3.6 V W Dr ρ.
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