The work done in moving a body of mass m by the centripetal force mv2/r over half the circumference of the circle of radius r with speed V is:
Correct answer: A. Zero
- A. Zero
- B. v2/r
- C. mv2/r
- D. πr2/mv2
Explanation
Centripetal force always acts towards the centre of the circle, perpendicular to the displacement. The work done by the centripetal force in moving the body over half the circumference of the circle is zero because the force and displacement are perpendicular. Options B, C, and D do not accurately represent the work done in this scenario.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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