The weight of a pilot when diving down in a jet plane with an acceleration of 9.8m/s2 will become
Correct answer: D. Zero
- A. Double
- B. Half
- C. Negative
- D. Zero
Explanation
Weight of pilot = Original Weight + Apparent Weight = mg+(-ma) a= 9.8ms-2 So weight of pilot = 0
This question appeared on the ETEA MDCAT 2011 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
About Weightlessness and Artificial Gravity
Weightlessness means the apparent weight or supporting force on an object is zero, as in free fall or an orbiting spacecraft, not that gravity has disappeared. Artificial gravity is produced by centripetal acceleration, usually through rotation. Questions compare gravitational force, normal reaction, orbital motion and the sensation of weight.
Practise Gravitation
265 free Gravitation MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 11 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Weightlessness and Artificial Gravity questions
The pilot weighting 686N dived down with an acceleration of 9.8m sec-2 its apparent weight is
An object in a satellite orbiting around the Earth is weightless because:
The weight of a pilot diving down with an acceleration of 9.8ms -2 will become:
An object in a satellite orbiting around the earth is weightless because:
Once the space shuttle is in orbit at a radius R from earths's centre what force does the seat exert on the astronout?