The wavelength,of last spectral line in Lyman series in terms of Rydberg constant(R) is equal to:
Correct answer: C. 1/R
- A. R
- B. R2
- C. 1/R
- D. 1/R2
Explanation
The last line of a series is its series limit, where the electron falls from n = infinity. For the Lyman series 1/lambda = R(1/1^2 - 0) = R, so lambda = 1/R. This is the shortest wavelength and highest energy line the series produces.
This question appeared on the ETEA MDCAT 2005 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Atomic Spectra
Atoms emit or absorb light at specific wavelengths because electrons occupy quantized energy levels and change levels by absorbing or releasing photons. The topic covers emission and absorption spectra, spectral series, hydrogen’s line spectrum, energy-level transitions, and the relation between wavelength, frequency and photon energy.
Practise Atomic Spectra
356 free Atomic Spectra MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Atomic Spectra questions
The life time of an electron in state is times more than an ordinary excited state.
The lifetime of an ordinary excited state is:
Hydrogen atom in the ground state absorbs energy from the incident photon. Which makes a transition to energy level characterized by n=4 the number of lines observed are:
The transition from n = 4,5,6,.......... To n+3 in hydrogen spectrum gives
The shortest wavelength of radiation in Paschen series is:
The part of the electromagnetic spectrum in which Lyman series lies is: