The wave-number of the first line in the Balmer series of Hydrogen is 15200 cm-1. Wave number of the first line in Balmer series of Be3+ is:
Correct answer: A. 2.43 x 10^5 cm-1
- A. 2.43 x 10^5 cm-1
- B. 1.87 x 10^5cm-1
- C. 243 x 10^5 m-1
- D. 1.8 x 10^5 m-1
Explanation
The wave number is proportional to the square of the atomic number. So, we have the atomic number, squared, of Be as 16 and of hydrogen as 1. Following this, we will multiply the wave number of hydrogen by the atomic number square of Be divided by the atomic number square of H to get the wave number of Be.15200 x 16 = 243200 cm-1
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