The volume occupied by 16g of oxygen at STP is:
Correct answer: C. 11.02dm3
- A. 2.24dm3
- B. 22.4dm3
- C. 11.02dm3
- D. 1.24dm3
Explanation
According to Avogadro's Law and the molar mass of oxygen (O₂), which is approximately 32 g/mol, 1 mole of oxygen gas occupies 22.4 dm³ at STP. Since we have 16 g of oxygen, which is half of the molar mass, we would have half a mole of oxygen gas, occupying half the volume, which is 11.2 dm³. Therefore, the correct answer is 11.02dm3.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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