The volume occupied by 1.4 gram into it STP is
Correct answer: C. 1.12dm³
- A. 22.4dm³
- B. 11.2dm³
- C. 1.12dm³
- D. 1.4dm³
Explanation
At STP, one mole of an ideal gas occupies 22.4 dm³. The molar mass of N2 is 28 g/mol. Therefore, 1.4 grams of N2 is 0.05 moles (1.4 g ÷ 28 g/mol). The volume occupied by 0.05 moles is 0.05 moles × 22.4 dm³/mole = 1.12 dm³. Therefore, the correct answer is 1.12 dm³. The other options miscalculate the relationship between mass and molar volume at STP.
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