The volume occupied by 1.4 gram into it STP is
Correct answer: C. 1.12dm³
- A. 22.4dm³
- B. 11.2dm³
- C. 1.12dm³
- D. 1.4dm³
Explanation
At STP, one mole of an ideal gas occupies 22.4 dm³. The molar mass of N2 is 28 g/mol. Therefore, 1.4 grams of N2 is 0.05 moles (1.4 g ÷ 28 g/mol). The volume occupied by 0.05 moles is 0.05 moles × 22.4 dm³/mole = 1.12 dm³. Therefore, the correct answer is 1.12 dm³. The other options miscalculate the relationship between mass and molar volume at STP.
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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