The vapor pressures of benzene and toluene are 3 and 4/3 atmospheres respectively. A liquid feed of 0.4 moles of benzene and 0.6 moles of toluene is vaporised. Assuming that the products are in equilibrium, the vapor phase mole fraction of benzene is_________________?

Correct answer: B. 0.6

  • A. 0.4
  • B. 0.6
  • C. 0.8
  • D. 0.2

Explanation

For an ideal liquid mixture, the vapor contribution is proportional to x_iP_i^sat. Thus benzene contributes 0.4(3)=1.2 and toluene 0.6(4/3)=0.8, giving y_benzene=1.2/(1.2+0.8)=0.6.

Written and checked by , MS Computer ScienceLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

Practise Chemical Engineering Thermodynamics

598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemical Engineering questions like this

Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.

More Chemical Engineering Thermodynamics questions