The value of NA/(NA + NB), for steady state equimolal counter diffusion of two gases 'A' and 'B' is____________?
Correct answer: B. ∞
- A. 1
- B. ∞
- C. 0.5
- D. 2
Explanation
In equimolal counterdiffusion, the molar fluxes satisfy N_A = -N_B, so the total molar flux N_A + N_B is zero. The displayed ratio consequently has a zero denominator and is conventionally described as infinite.
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