The value of A in the following reaction is: 4 Be9 + 2He4 = 6CA + on1
Correct answer: C. 12
- A. 14
- B. 10
- C. 12
- D. 16
Explanation
On the left-hand side of the reaction, we have the sum of the mass numbers of the reactants: Mass number before the reaction = 9 (mass number of 4Be9) + 4 (mass number of 2He4) = 13. On the right-hand side of the reaction, we have the sum of the mass numbers of the products: The mass number after the reaction = A (mass number of 6CA) + 1 (mass number of 0n1). Since the reaction involves a neutron as one of the products, its mass number is 1. Therefore, the mass number after the reaction is A + 1. Now, equating the mass numbers before and after the reaction: 13 (mass number before the reaction) = A + 1 (mass number after the reaction). To find the value of A, we can rearrange the equation: A = 13 - 1 = 12. So, the value of A for the unknown isotope ^6_C A is 12.
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Atomic nuclei contain positively charged protons and electrically neutral neutrons, collectively called nucleons. Questions use atomic number, mass number and nuclear notation to identify isotopes, isobars and isotones, and may connect nuclear composition with nuclear charge, mass defect, binding energy and the stability of the nucleus.
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