The time period T and the angular speed omega of circular motion are related by
Correct answer: C. T equals 2 pi over omega
- A. T equals omega over 2 pi
- B. T equals 2 pi omega
- C. T equals 2 pi over omega
- D. T equals omega squared
Explanation
One complete revolution covers 2 pi radians, so the time taken is 2 pi divided by the angular speed. A larger omega therefore means a shorter period, which is the inverse relationship the formula expresses. Frequency, being the reciprocal of the period, is omega divided by 2 pi.
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About Angular Velocity
Angular velocity describes how quickly angular displacement changes with time, with ω = Δθ/Δt and units of radians per second. Questions relate angular and linear motion through v = rω, use the direction given by the right hand rule, and distinguish angular velocity from angular acceleration and ordinary frequency.
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