The thermal radiative flux from a surface of emissivity = 0.4 is 22.68 kW/m2. The approximate surface temperature (K) is (Stefan-Boltzmann constant = 5.67 x 10^-8 W/m2.K4) ?
Correct answer: A. 1000
- A. 1000
- B. 727
- C. 800
- D. 1200
Explanation
From q = εσT⁴, T = [22,680/(0.4 × 5.67 × 10⁻⁸)]¹/⁴, which is approximately 1000 K. The emissivity must be included, so using σT⁴ alone would give an incorrect lower temperature.
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