The thermal efficiency of a reversible heat engine operating between two given thermal reservoirs is 0.4. The device is used either as a refrigerator or as a heat pump between the same reservoirs. Then the coefficient of performance as a refrigerator (COP)R and the co-efficient of performance as a heat pump (COP)HP are _______________?
Correct answer: C. (COP)R = 1.5; (COP)HP = 2.5
- A. (COP)R = (COP)HP = 0.6
- B. (COP)R = 2.5; (COP)HP = 1.5
- C. (COP)R = 1.5; (COP)HP = 2.5
- D. (COP)R = (COP)HP = 2.5
Explanation
For a reversible engine, η = 1 − T_L/T_H = 0.4, so T_L/T_H = 0.6. Therefore, (COP)R = 0.6/0.4 = 1.5 and (COP)HP = (COP)R + 1 = 2.5.
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