The speed of electron in the first Bohr orbit is:
Correct answer: A. 2.19 x 10^6 ms-1
- A. 2.19 x 10^6 ms-1
- B. 2.19x 10- 6 ms- 1
- C. 2.19 x 10^4 ms-1
- D. 2.19 x 10^-4 ms-1
Explanation
According to Bohr's model of the hydrogen atom, the speed of an electron in the first Bohr orbit can be calculated using the formula: v = Ze² / 2εοh Where, Atomic number = Z = 1 Charge = e = 1.602 × 10-19 C Permittivity of free space = εο =8.854×10-12 C²/Nm² Planck's constant = h = 6.626 × 10-34 J's Putting the values in the above formula, we get: v = 1 × (1.602 × 10-19)² / 2 × (8.854×10-12) × (6.626 × 10-34) v = 2.19 × 106 ms-1
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