Asked in PMC Practice Test 16 (2021) 2021Moderate

The shortest distance between two points on the wave that have a phase difference of (pi/3) is 5 cm. What is its wavelength?

Correct answer: C. 30 cm

  • A. 10 cm
  • B. 20 cm
  • C. 30 cm
  • D. 40 cm

Explanation

Phase difference = 2(PI)/ lambda x path difference Where , Phase difference = (PI)/3 Path difference = 5 The equation becomes , (pi)/3 = 2(pi) / lambda x 5 Wavelength = 3x2x5 Wavelength = 30 cm Mathematically option A,B & D are incorrect

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About Progressive Waves

Progressive waves transfer energy through a medium or space while particles oscillate about their equilibrium positions. The work includes amplitude, wavelength, frequency, period, phase difference, wave speed and the progressive wave equation, while distinguishing travelling waves from stationary waves, where the pattern has fixed nodes and antinodes.

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