The series limit for the Balmer series of hydrogen spectrum occurs at 3664 A°. Calculate Ionization energy of hydrogen atom.
Correct answer: C. 5.425 x 10^-19 J
- A. 21.7 x 10^-19 J
- B. 6.626 x 10^-34 J
- C. 5.425 x 10^-19 J
- D. 3664 x 10^-10 J
- E. 3 x 10^8 J
Explanation
The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J so option C is the only correct option.
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Atoms emit or absorb light at specific wavelengths because electrons occupy quantized energy levels and change levels by absorbing or releasing photons. The topic covers emission and absorption spectra, spectral series, hydrogen’s line spectrum, energy-level transitions, and the relation between wavelength, frequency and photon energy.
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