The researcher has prepared a sample of 1-bromopropane from 10 gram of 1-propanol after purification he made 12 gram of product which of the following is percent yield
Correct answer: A. 58%
- A. 58%
- B. 70%
- C. 50%
- D. 90%
Explanation
Mr of 1-propanol= 60g/molMr of 1-bromopropane= 122.9g/mol60g => 122.9g10g => xgx= 20.5Percentage Yield = (Actual Yield / Theoretical Yield) × 100 = 12/20 x100 = 58%
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
Practise Fundamental Concepts of Chemistry
898 free Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Fundamental Concepts of Chemistry questions
In the reaction 4NH3+5O2--4NO+6H2O.When one mole of ammonia and one mole of Oxygen are made to react to completion then
If two mole of H2S and 11.2 dm³ of SO2 at STP react according to the following equation SO2+2H2S---2H2O+3SWhat will be the number of moles of sulphur formed in the reaction?
A gaseous hydrocarbon gives upon combustion 0.72 gram of water in 3.08 gram of CO2 the empirical formula of the hydrocarbon is
The stoichiometric calculations for a chemical reaction result in
The actual yield is less than theoretical yield because
8 gram of CH4 on combustion give 18 gram of CO2 calculate percentage yield