The relationship between the root mean square (R.M.S) current ((I_{{rms}})), peak current ((I_{{peak}})), and frequency ((f)) in an alternating current circuit with a resistor is given by the formula:
Correct answer: D. 5.66 A
- A. 20 A
- B. 20.66 A
- C. 6.66 A
- D. 5.66 A
Explanation
[ I_{{rms}} = frac{I_{{peak}}}{sqrt{2}} ]We can rearrange this formula to find the peak current:[ I_{{peak}} = I_{{rms}} times sqrt{2} ]Let's calculate the peak current using the given values:[ I_{{peak}} = 4.0 , {A} times sqrt{2} ][ I_{{peak}} approx 4.0 , {A} times 1.414 ][ I_{{peak}} approx 5.656 , {A} ]So, the calculated peak current is approximately 5.656 A.Now, let's compare this with the provided options:
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