The relation between ß and a is______________?
Correct answer: C. ß = a / (1 - a )
- A. ß = 1 / (1 - a )
- B. ß = (1 - a ) / a
- C. ß = a / (1 - a )
- D. ß = a / (1 + a )
Explanation
Since α = I_C/I_E and I_E = I_C + I_B, rearranging gives β = I_C/I_B = α/(1 − α). Therefore option c is the required relation.
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