The reaction, A(g) + B(g) ⇋ C(g) +D(g) is studied in a one litre vessel at 250oC. The initial concentration of A was 3n and B was n. When equilibrium was attained, equilibrium concentration of C and B were the same. What is the concentration of D at equilibrium?
Correct answer: A. n/2
- A. n/2
- B. (3n-1)/2
- C. (n-1)/3
- D. n
Explanation
Given the equilibrium is,A(g) + B(g) ⇋ C(g) +D(g)Initial concentration: 3n, n, 0, 0Concentration at equilibrium: 3n-x, n-x, x, xAt equilibrium concentration of C is equal to the concentration of B,N-x = x2x = nX = n/2Concentration of D at equilibrium = x = n/2
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About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
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