The ratio of the depth of flow to the diameter of the channel for maximum discharge in a circular channel in open channel flow is________________?
Correct answer: C. 0.95
- A. 0.1
- B. 0.55
- C. 0.95
- D. 1.85
Explanation
For maximum discharge, maximizing A^(5/3)/P^(2/3) for a circular section gives a flow depth of about 0.94 times the diameter. Hence the closest option is 0.95.
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