The ratio of average power to the peak power in a resistive AC circuit is.
Correct answer: A. 1:2
- A. 1:2
- B. 2:1
- C. 1:1
- D. None
Explanation
In a resistive AC circuit, the average power is P (avg) = I (rms) × V (rms) = (I (peak) /√2) × (V (peak) /√2) = (I (peak) × V (peak) )/2. The peak power is P(peak) = I(peak) × V(peak) . The ratio P(avg) / P(peak) is therefore 1/2.
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Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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