The ratio of average power to the peak power in a resistive AC circuit is.
Correct answer: A. 1:2
- A. 1:2
- B. 2:1
- C. 1:1
- D. None
Explanation
In a resistive AC circuit, the average power is P (avg) = I (rms) × V (rms) = (I (peak) /√2) × (V (peak) /√2) = (I (peak) × V (peak) )/2. The peak power is P(peak) = I(peak) × V(peak) . The ratio P(avg) / P(peak) is therefore 1/2.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Alternating Current
Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
Practise Alternating Current
592 free Alternating Current MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Alternating Current questions
In the case of an AC circuit, the power loss in a resistive circuit.
Which of these effects does not depend on the direction of current?
The use of a capacitor filter in a rectifier circuit gives satisfactory performance only when the load:
If Irms × Vrms = 100 watts, then Ipeak × Vpeak= ?
If the peak current is increased by a factor of 2, then the percentage change in the peak power is (assume voltage is constant);
If the peak value of current and voltage are doubled, then what is the percentage change in average power?