The rate of the reaction, X → Y, quadruples when the concentration of 'X' is doubled. The rate expression for the reaction is, r = K Cx n, the value of 'n' in this case will be_______________________?
Correct answer: C. 2
- A. 0
- B. 1
- C. 2
- D. 3
Explanation
Doubling concentration changes the rate by 2^n. Since the rate becomes four times larger, 2^n = 4 = 2^2, giving a second-order dependence on X.
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