The rate of the reaction, X → Y, quadruples when the concentration of 'X' is doubled. The rate expression for the reaction is, r = K Cx n, the value of 'n' in this case will be_______________________?
Correct answer: C. 2
- A. 0
- B. 1
- C. 2
- D. 3
Explanation
Doubling concentration changes the rate by 2^n. Since the rate becomes four times larger, 2^n = 4 = 2^2, giving a second-order dependence on X.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Reaction Engineering
395 free Chemical Reaction Engineering MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Reaction Engineering questions
In case of a P.F.R., there__________________________?
For an ideal mixed flow reactor (CSTR), the exit age distribution E(t) is given by __________________?
An irreversible first order reaction is being carried out in a CSTR and PFR of same volume. The liquid flow rates are same. The relative conversion will__________________?
The rate of a homogeneous reaction is a function of__________________?
For series reaction, the relative yield__________________?
In autocatalytic reactions ?