The rate of a gaseous reaction is given by K[A][B]. If the volume of the vessel containing these gases is reduced to 1/4th of the initial volume, the rate of reaction relative to the original rate would be:
Correct answer: A. 16/1
- A. 16/1
- B. 1/16
- C. 4/1
- D. 1/8
- E. 8/1
Explanation
If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
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Reaction kinetics relates reaction rate to concentration, temperature, surface area and catalysts. Questions cover rate laws, reaction order, rate constants, activation energy and the activated complex, including how a catalyst lowers the activation energy without changing the overall energy change or equilibrium position.
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