The rate expression for a heterogeneous catalytic reaction is given by, - rA = K.KA PA(1 + KA.PA + KR.PR), where K is surface reaction rate constant and KA and KR are absorption equilibrium constants of A and R respectively. If KR PR >> (1 + KA PA), the apparent activation energy EA is equal to (given E is the activation energy for the reaction and ΔHR and ΔHA are the activation energies of adsorption of R and A) ?
Correct answer: C. E + ΔHA - ΔHR)
- A. E
- B. E + ΔHA
- C. E + ΔHA - ΔHR)
- D. ΔHA + ΔHR
Explanation
When the denominator is dominated by K_RP_R, the rate is proportional to K K_A/K_R. Combining the temperature dependences gives the apparent activation energy E + ΔH_A − ΔH_R.
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