Asked in UHS MDCAT 2009 2009Moderate

The rate equation determined experimentally for this reaction: (CH3)3―C―Br + H2O → (CH3)3―C―OH + HBr, is Rate = k[(CH3)3CBr] Hence it is which of the follwing?

Correct answer: B. Pseudo First Order

  • A. Fractional Order
  • B. Pseudo First Order
  • C. First Order
  • D. Second Order

Explanation

Explanation:The reaction is pseudo first order. Water is in excess as it is the solvent as a result will not affect the reaction order. If we don't take water in consideration the order of reaction is 1, because the exponent of [(CH3)3-C-Br] is one. As water is not taken into consideration the reaction is pseudo first order.

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About Order of Reaction

Reaction order shows how the rate depends on the concentration of each reactant, as expressed in the rate law. Coverage includes zero, first and second-order reactions, integrated rate equations, half-life, units of rate constants and the distinction between overall order and molecularity.

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