The range of projectile is 30° at R30 and 60° at R60 then
Correct answer: A. R30 = R60
- A. R30 = R60
- B. R30 = 2R60
- C. 2R30 = R60
- D. R30 = R60 if initial velocities are the same
Explanation
R= v2sin(2θ) / gThe following is the solution to this question.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
A projectile is launched at point 0 and follows the path OPQRS as shown. Air resistance may be neglected. Which statement is true for the projectile when it is at the highest point Q of its path?
In the given diagram, the coach moves from position A to B to C to D. What is the coach's resulting displacement and distance of travel?
Why do ballistic missiles fall in some circumstances of precision?
The displacement-time graph of a particle moving with uniform velocity is
The ratio of distance to displacement along a semicircle of radius r is
Which of the following changes when a particle is moving with uniform velocity?