The radius of curvature of the path of a charged particle moving in a static uniform magnetic field is:
Correct answer: B. Directly proportional to the magnitude of the linear momentum of the particle
- A. Directly proportional to the magnitude of the charge on the particle
- B. Directly proportional to the magnitude of the linear momentum of the particle
- C. Directly proportional to the kinetic energy of the particle
- D. Inversely proportional to the magnitude of the magnetic field
Explanation
The radius of the circular path is given by r = mv/qB. The term mv is the linear momentum (p) of the particle. Therefore, the radius is directly proportional to the momentum (r = p/qB).
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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