The question is given below:

Explanation

L = n * (λ/4)where 'n' represents the harmonic number (n = 1, 3, 5, ... for the first, second, third, etc., resonances).Let's analyze each length shown in the image: * For n = 1 (First Resonance - L1): The image correctly shows L1 as the first resonance, where a node is at the water surface and an antinode is at the open end. L1 = 1 * (λ/4) = λ/4 This matches the value given in the diagram. * For n = 2 (Second Resonance - L2): The "second resonance" in this context refers to the second possible resonant length for the closed-end tube, which corresponds to the third harmonic (n=3). Here, there will be two nodes and two antinodes, or generally (2n-1) nodes and antinodes. L2 = 3 * (λ/4) = 3λ/4 * For n = 3 (Third Resonance - L3): The "third resonance" refers to the third possible resonant length, which corresponds to the fifth harmonic (n=5). L3 = 5 * (λ/4) = 5λ/4