The pH of 10-3 mol dm-3 of an aqueous solution H2SO4 is:
Correct answer: B. 2.7
- A. 3.0
- B. 2.7
- C. 2.0
- D. 1.5
Explanation
Given pH= 10-3 After ionization, H2SO4 ⇔ 2H+ + SO4- [H+] from H2SO4 = 2x10-3 We know that pH = -log10 [H+] pH = -log10 (2 x 10-3) = 3 - log2 = 3 - 1.414 = 2.69M
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About Acids, Bases and Salts
Acid and base behaviour is explained through the Bronsted-Lowry transfer of protons and the Lewis donation or acceptance of electron pairs. The topic includes pH, pOH, ionisation and water equilibrium, plus salt formation and hydrolysis, where a salt solution may become acidic, basic or neutral.
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