The paratrooper of mass 80 kg descends vertically at a constant velocity of 3.0 ms-¹ . Taking the acceleration of free fall as 10 ms-¹ find out what is the net force acting on him? (g=10ms-²)
Correct answer: A. Zero
- A. Zero
- B. 800 N upward
- C. 800 N downward
- D. 24 N downward
Explanation
The net force is zero bcz there is no acceleration. The strings of parachute are pulling against him in the upward direction with a force equal to his weight which is equal and opposite to his weight due to pull of gravity downward.
This question appeared on the ETEA MDCAT 2009 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Newton's Laws of Motion
Newton’s laws explain inertia, the relation between net force and acceleration, and action-reaction pairs. Questions involve free-body diagrams, balanced and unbalanced forces, F = ma, force as the rate of change of momentum, and identifying genuine third-law pairs, which act on different bodies.
Practise Force and Motion
1,421 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Newton's Laws of Motion questions
A person haviog a mass of 60kg exerts a horizontal force of 150N in horizontal floor with constant velocity, Net force is:
A body of mass 1 kg is suspended from a balance in the elevator, which is accelerating downward with an acceleration of 4ms-1 the reading of the balance will be:
A string passes over a smooth pulley and carries a 3kg mass at one end and a 5kg mass at the other end. The acceleration of the masses is:
When an object slides at constant speed down an inclined plane, the coefficient of fraction may be approximately:
Newton's second law of motion establishes a relationship between.
The property of the moving object by virtue of which it exerts force on the object that tries to slop it is: