The oxidation of propan-2-ol with acidified potassium dichromate gives
Correct answer: D. propanone
- A. propanal
- B. propanoic acid
- C. propene
- D. propanone
Explanation
Propan-2-ol is a secondary alcohol, so oxidation removes the single hydrogen on the carbinol carbon and leaves a ketone, which resists further oxidation because no hydrogen remains on that carbon. A primary alcohol would give an aldehyde and then an acid. This difference in oxidation product is the standard way of identifying the class of an unknown alcohol.
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About Alcohols
Alcohols contain a hydroxyl group attached to a saturated carbon atom and are classified as primary, secondary or tertiary. Their nomenclature, hydrogen bonding, acidity, oxidation, dehydration, reaction with sodium and conversion to haloalkanes are covered, along with the distinction between alcohols and phenols, where the hydroxyl group is attached directly to an aromatic ring.
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