The oxidation of propan-2-ol with acidified potassium dichromate gives
- A. propanal
- B. propanoic acid
- C. propene
- D. propanone
Explanation
Propan-2-ol is a secondary alcohol, so oxidation removes the single hydrogen on the carbinol carbon and leaves a ketone, which resists further oxidation because no hydrogen remains on that carbon. A primary alcohol would give an aldehyde and then an acid. This difference in oxidation product is the standard way of identifying the class of an unknown alcohol.
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