The oxidation number of Nickel in [Ni(CO)]4] is:
Correct answer: A. 0
- A. 0
- B. 8
- C. 6
- D. 4
Explanation
Let 'x' be the oxidation number of 'Ni' in Ni(CO)4.Since the overall charge of the complex is 0, the sum of the oxidation states of all elements in it should be equal to 0.Therefore, x+4(0) = 0, because CO has no oxidation charge.Hence, x=0.Thus, the oxidation number of Ni in Ni (CO)4 is 0.
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About Transition Elements
Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.
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