The Oxidation number in [MnO4]2- is?
Correct answer: C. +6
- A. +7
- B. -7
- C. +6
- D. -6
Explanation
To determine the oxidation number of manganese (Mn) in the permanganate ion [MnO4]2-, we can assign oxidation numbers to the other elements and then use the overall charge of the ion.The sum of the oxidation numbers in a compound or ion must equal the overall charge. In this case, the overall charge of [MnO4]2- is -2Let's assign the oxidation numbers:Oxygen typically has an oxidation number of -2.The total oxidation number of oxygen in the permanganate ion is 4 * (-2) = -8Now, let's denote the oxidation number of manganese as xThe sum of the oxidation numbers must equal the overall charge: x + (-8) = -2Solving for x we get : So, the oxidation number of manganese in [MnO4]-2 is +6.
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About Transition Elements
Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.
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