The order of force of repulsion between Lone pairs and Bond pairs is?
Correct answer: D. Lone pair lone pair repulsion> lone pair Bond pair repulsion> Bond pair Bond pair repulsion
- A. Lone pair Bond -pair repulsion > lone pair lone pair repulsion> Bond pair Bond pair repulsion
- B. Bond pair -Bond pair repulsion> lone pair lone pair repulsion> lone pair Bond pair repulsion
- C. Lone pair lone pair repulsion> Bond pair Bond pair repulsion> lone pair Bond pair repulsion
- D. Lone pair lone pair repulsion> lone pair Bond pair repulsion> Bond pair Bond pair repulsion
Explanation
It is true because in lone pairs the electrons are not involved in bonding and are free hence the repulsion is greater. The lone pair -lone pair repulsion is greater than lone pair -bond pair repulsion which is slightly greater than bond pair -bond pair because of one free electron and hence the given order is correct
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Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.
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