The orbit of electrons moving at a rate of 1.6 x 10^6 m/s in a uniform magnetic field of 1.0 x 10-3. The radius of orbit of the electron is: Take mo as 9.1 x 10^-31 kg and e as 1.6 x 10^-19 C.
Correct answer: A. 9.1 x 10^-3 m
- A. 9.1 x 10^-3 m
- B. 9.1 x 10^-2 m
- C. 1.9 x 10^-3 m
- D. 1.9 x 10^-2 m
- E. 9.1 x 10^-1 m
Explanation
The radius of the orbit of an electron moving in a uniform magnetic field is given by the equation: r = mv/eB Where r is the radius of the orbit, m is the mass of the electron, v is the velocity of the electron, e is the charge on the electron, and B is the magnitude of the magnetic field. Substituting the given values, we have: r = (9.1 x 10-31 kg) x (1.6 x 106 m/s) / (1.6 x 10-19 C) x (1.0 x 10-3 T) r = 9.1 x 10-3 m Therefore, the correct answer is A.
This question appeared on the NUMS 2019 (cancelled sitting) paper, which you can sit online with every answer explained.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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