The number of electrons present in n = 2, l = 1 and m = -1, 0, +1 are:
Correct answer: A. 6
- A. 6
- B. 2
- C. 8
- D. 10
- E. 18
Explanation
n is the principal quantum number and indicates the number of shells. n = 2 indicates that the second shell is being discussed. l is the azimuthal quantum number and indicates the number of subshells. l = 0 means s subshell, l = 1 means p subshell, and so on. m is the magnetic quantum number and indicates the orientation of orbitals in the subshells. m ranges from -1 to +1 through 0. Since m = -1, 0, +1, this means that all three sub-orbitals; 2px, 2py, 2pz are taken into consideration. Since all of these have 2 electrons each, the total number of electrons in them is 6.
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