The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x1. x2, where A is a constant. The corresponding equation for ln y1, where y1 is the activity co-efficient of component 1, is__________________?
Correct answer: A. A . x22
- A. A . x22
- B. Ax1
- C. Ax2
- D. Ax12
Explanation
The activity coefficient follows from differentiating the total excess Gibbs energy with respect to the amount of component 1. For gE/RT = A x1x2, this gives ln γ1 = A x2², corresponding to option a.
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