The maximum wavelength of Lyman series is:

Correct answer: A. 4/3R

  • A. 4/3R
  • B. 1/R2
  • C. C/R
  • D. 1/RC

Explanation

The maximum wavelength of the Lyman series occurs when an electron in a hydrogen atom undergoes a transition from the n=2 energy level to the n=1 energy level. This transition corresponds to the emission of a photon with the maximum wavelength in the Lyman series. The wavelength of this photon can be calculated using the Rydberg formula:1/λ = R(1/1^2 - 1/2^2)= Rh(3/4)λ= 4/3RhWhere λ is the wavelength of the photon, R is the Rydberg constant (1.097 x 10^7 m^-1), and the values of n are 1 and 2 for the n=1 and n=2 energy levels, respectively.Solving for λ, we get:λ = 121.6 nm.Therefore, the maximum wavelength of the Lyman series is 121.6 nm.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Atomic Spectra

Atoms emit or absorb light at specific wavelengths because electrons occupy quantized energy levels and change levels by absorbing or releasing photons. The topic covers emission and absorption spectra, spectral series, hydrogen’s line spectrum, energy-level transitions, and the relation between wavelength, frequency and photon energy.

Practise Atomic Spectra

356 free Atomic Spectra MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Atomic Spectra questions