The maximum discharge through a circular channel takes place, when the depth of the fluid flow is ______________ times the pipe diameter?
Correct answer: D. 0.95
- A. 0.25
- B. 0.5
- C. 0.66
- D. 0.95
Explanation
For maximum discharge in a circular open channel, the hydraulic radius is optimized at a depth of about 0.94 times the diameter. The nearest listed value is 0.95, not 0.66, which corresponds to a different geometric condition.
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