The main difference between a catalyst and an enzyme is:
Correct answer: C. Catalysts are inorganic while enzymes are organic in nature
- A. Enzymes are sharp in action than catalyst
- B. Catalysts are used in larger concentration than enzymes
- C. Catalysts are inorganic while enzymes are organic in nature
- D. Enzymes need pH while catalysts do not need something
Explanation
Catalyst: Substance that increases the rate of a chemical reaction without being consumed. Can be organic or inorganic.Enzyme: A biological catalyst, always organic (proteins or RNA), highly specific, and works under mild conditions (temperature, pH).Main difference: enzymes are organic molecules (proteins or RNA), while many chemical catalysts are inorganic.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
Practise Chemical Equilibrium
625 free Chemical Equilibrium MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Chemical Equilibrium questions
The equilibrium constant of a reaction is 300. If the volume of the reaction flask is tripled, the equilibrium constant is:
2SO2 (g)+ O2 (g),⇌ 2SO3 (g), in the above reaction Kp and Kc are related as
For a gaseous reaction, A2 + 2B 2AB, the following rate data obtained at 250K.Calculate the rate of formation of AB when [A2] = 0.02 M and [B] = 0.01 M at 250K.
The rate law for the reaction, A---C+k is given as: Rate=K[A]The unit of K will be:
A zero order reaction is one whose rate is independent of the:
Chemical equilibrium is not associated with: