The magnitude of force experienced by a stationary charged particle in a uniform magnetic field is
Correct answer: C. Zero
- A. \(qv \times B\
- B. Minimum
- C. Zero
- D. Maximum
Explanation
When a stationary charged particle is placed in a uniform magnetic field, it does not experience any force, assuming it remains stationary.### Explanation:The force (\(F\)) experienced by a charged particle (\(q\)) moving with velocity (\(v\)) in a magnetic field (\(B\)) is given by the formula:\[ F = qvB \sin(\theta) \]Where:- \(q\) = charge of the particle- \(v\) = velocity of the particle- \(B\) = magnetic field strength- \(\theta\) = angle between the velocity vector and the magnetic field vector When a charged particle is stationary (not moving), the force it experiences in a uniform magnetic field is zero.
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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