The magnetic force experienced by a charge particle moving in a magnetic field will be minimum when it moves:

Correct answer: A. Parallel to magnetic field

  • A. Parallel to magnetic field
  • B. Both option A and C
  • C. Perpendicular to magnetic field
  • D. None of these

Explanation

The magnetic force experienced by a charged particle moving in a magnetic field is given by the equation:\[ F = q \cdot v \cdot B \cdot \sin \theta \]where:- \( F \) is the magnetic force,- \( q \) is the charge of the particle,- \( v \) is the velocity of the particle,- \( B \) is the magnetic field strength,- \( \theta \) is the angle between the velocity vector and the magnetic field vector.When the charged particle moves parallel to the magnetic field lines, the angle \( \theta \) is 0 degrees. In trigonometry, \(\sin 0^\circ\) is equal to 0. Therefore, the term \(\sin \theta\) becomes 0, resulting in the magnetic force \( F = 0 \). This means that the force experienced by the charged particle is at its minimum when it moves parallel to the magnetic field.

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About Electromagnetism

Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.

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