The magnetic flux linked with a solenoid of area 'A', having 'N' turns at right angle to magnetic field is:
Correct answer: A. NBA
- A. NBA
- B. BA
- C. ½ NBA
- D. BAcos(θ)
Explanation
In this scenario we have to find the magnetic flux linkage. Since we already have the solenoid's wire being perpendicular to the field lines, we don't need cos Theta in the equation. Moreover, BA gives us the flux whereas multiplying BA by N, which is the number of turns, gives us the total flux that is the flux linkage.
This question appeared on the UHS MDCAT 2017 paper, which you can sit online with every answer explained.
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About Magnetic Flux
Magnetic flux measures the magnetic field passing through a surface, calculated for a uniform field as Φ = BA cos θ, where θ is the angle between the field and the surface normal. Questions involve area, field strength and orientation, the weber as its unit, and the distinction between flux and magnetic field.
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