The incorrect statement for 14g of CO is:

Correct answer: A. It occupies 2.24 litre at STP

  • A. It occupies 2.24 litre at STP
  • B. It corresponds to the same number of moles for 14g of CO and 14 g of N2
  • C. It corresponds to 0.5 mol of CO
  • D. It corresponds to 3.01 x 10^23 molecules of CO

Explanation

The question is asking for the statement which is incorrect for 14 g of CO. Upon solving each of the options we get the following results:A)22.4 dm3 at stp = 1 mole , 1 litre = 1dm3n(number of moles) of CO = mass in g/mr = 14/28 = 0.5 mol1 mol : 22.4 dm3 0.5 mol : x = 0.5 x 22.4 = 11.2 dm3/11.2 litre ;hence, this statement about 14g of CO is incorrect. B) n(number of moles) of CO = mass in g/mr = 14/28 = 0.5 mol n(number of moles) of N2 = mass in g /mr = 14/28 = 0.5 mol ;hence, this statement is correct.C) n(number of moles) of CO = mass in g/mr = 14/28 = 0.5 mol ; hence, this statement is correct. D) n(number of moles) of CO = mass in g/mr = 14/28 = 0.5 mol 1 mol : 6.02 x 1023 0.5mol : x = 0.5 x 6.02 x1023 = 3.01 x1023 ; hence, this option is also correct. Therefore, option A is the right answer as it is the only option stating incorrect information about 14g of CO.

Written and checked by , M.Phil ChemistryLast updated
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