The hydraulic radius for flow in a rectangular duct of cross-sectional dimension H, W is___________________?
Correct answer: B. HW/2 (H + W)2
- A. √(HW/π)
- B. HW/2 (H + W)2
- C. HW/4 (H + W)2
- D. 2HW/(H + W)
Explanation
Hydraulic radius equals flow area divided by wetted perimeter. For a rectangular duct, Rₕ = HW/[2(H+W)], which is the expression intended by option b despite its poor formatting.
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