The hybridization of carbon in diamond, graphite and acetylene is respectively:
Correct answer: C. sp3, sp2, sp
- A. sp3, sp, sp2
- B. sp, sp2, sp3
- C. sp3, sp2, sp
- D. sp2, sp3, sp
Explanation
The hybridisation of carbon atom in diamond, graphite and acetylene are respectively sp3, sp2, sp. In diamond, each carbon combine with 4 other carbon atoms with four sigma bonds. Hence, the hybridization of carbon is sp3. In graphite, each carbon combines with 3 other carbon atoms with three sigma bonds. so sp2 hybridization. In acetylene, one carbon combines with another carbon atom with three bonds (1 sigma and 2 pi bonds). so sp2 hybridization.
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