The halogen which reacts spontaneously with gold(Au) to form Au+s is
Correct answer: A. F₂ (Fluorine gas)
- A. F₂ (Fluorine gas)
- B. Cl₂ (Chlorine gas)
- C. Br₂ (Bromine gas)
- D. I₂ (Iodine)
Explanation
Fluorine's exceptional reactivity: Among the halogens, only fluorine gas (F₂) is powerful enough to react directly with gold under normal conditions, forming gold(I) fluoride (The reaction equation is:Au+ 3F2 →AuF3). Fluorine's high reactivity allows it to spontaneously react with gold.In summary, the correct answer is (a) F₂, as fluorine is the only halogen reactive enough to spontaneously form gold fluoride compounds under normal conditions.
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About Transition Elements
Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.
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