The half-life of a radioactive isotope is 6.5 hours. If there are initially 48 x 10^32 atoms of this isotope, the number of atoms of this isotope remaining after 26 hours is:
Correct answer: B. 3 x 10^32
- A. 12 x 10^32
- B. 3 x 10^32
- C. 6 x 10^32
- D. 6 x 10^4
Explanation
Number of half-lives, n = 26h/6.5hr = 4Amount remaining after n half-lives = 1/2n( No)Amount remaining after 4 half-lives = 1/24 (No)= 1/16(48 x 1032 ) = 3 x 1032
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