The ground state energy of H-atom is 13.6 eV. The energy needed to lonize H-atom from its second excited state is:
Correct answer: A. 1.51 eV
- A. 1.51 eV
- B. 3.4 eV
- C. 13.6 eV
- D. 12.1 eV
Explanation
The energy required to ionize a hydrogen atom from a given state is the difference between the energy of that state and the energy of the ionized state (0 eV). The ground state energy of hydrogen is -13.6 eV. The energy of the second excited state (n=3) is given by the formula E = -13.6/n² eV, which results in an energy of -1.51 eV. Therefore, the energy required to ionize the hydrogen atom from the second excited state is 1.51 eV. Options B, C, and D do not correctly describe the energy required from the second excited state.
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The hydrogen spectrum consists of discrete emission lines produced when electrons fall between quantised energy levels and release photons. Questions use the Rydberg equation, photon energy and wavelength, and identify the Lyman, Balmer, Paschen, Brackett and Pfund series, which differ from continuous spectra.
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